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Message-ID: <08B08C9FA5EBD311A2CC009027D5BF81032B0F9E@remailnt2-re01.westat.com>
From: Francis Harvey <HARVEYF1 AT WESTAT DOT com>
To: "'cygwin AT cygwin DOT com'" <cygwin AT cygwin DOT com>
Subject: GCC and getcwd
Date: Thu, 31 Jan 2002 13:21:29 -0500
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Greetings,

This isn't directly a cygwin question, but hopefully somebody has a
suggestion or a new topic I should search on:

I have a working C program created with GCC 2.95.2-6 and Cygwin
dll 1.1.7.  I realize both of these are a little old, but I think
I have a conceptual problem rather than a version issue.

I want to find the current directory that the executable file is in,
so I can open a text file in the same directory.  The executable
is on the k drive, but my code doesn't return the correct path:

/* Begin code sample */
main()
{
	  FILE *testfile;
        char buffer[100];
        int size = 100;

        testfile = fopen("c:\\windows\\desktop\\test.txt","w");
        getcwd(buffer,size);
        fprintf(testfile,"buffer = %s\n",buffer);
}
/* End code sample */

which returns:
buffer = /cygdrive/c/WINDOWS/DESKTOP

I am probably using the wrong function or possibly need to look
at a Windows-based group of functions?

TIA for any ideas.

Francis R. Harvey III
WB303, x3952
harveyf1 AT westat DOT com

VB programmers know the wisdom of Nothing

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