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Message-ID: <80575AFA5F0DD31197CE00805F650D7602CFF4@wilber.adroit.com>
From: "Robinow, David" <drobinow AT dayton DOT adroit DOT com>
To: "'cygwin AT cygwin DOT com'" <cygwin AT cygwin DOT com>
Subject: RE: Makefile that runs w.o. changes on Cygwin & Linux: how to do 
	"rm  -f $(TARGET)"?
Date: Thu, 6 Sep 2001 17:39:10 -0400 
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	charset="iso-8859-1"

MACH=`uname -s`
case "${MACH}" in
 CYGWIN*)
    EXE=".exe"
    ;;
 *)
    EXE=""
    ;;
esac

rm -f thing${EXE}

> -----Original Message-----
> From: Karr, David [mailto:david DOT karr AT cacheflow DOT com]
> Sent: Thursday, September 06, 2001 4:38 PM
> To: 'cygwin AT cygwin DOT com'
> Subject: Makefile that runs w.o. changes on Cygwin & Linux: how to do
> "rm -f $(TARGET)"?
> 
> 
> I have a little test application that I want to build and run 
> without change
> on Cygwin and Linux.  It almost works perfectly, except for 
> the "clean"
> target.  Is there any way to reference "thing" and have it 
> mean "thing" on
> Linux, but "thing.exe" on Cygwin?

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