Mailing-List: contact cygwin-help AT sourceware DOT cygnus DOT com; run by ezmlm List-Subscribe: List-Archive: List-Post: List-Help: , Sender: cygwin-owner AT sources DOT redhat DOT com Delivered-To: mailing list cygwin AT sources DOT redhat DOT com Message-ID: From: klaus DOT berndl AT sdm DOT de To: cygwin AT sources DOT redhat DOT com Subject: AW: Starting Programms in the background Date: Thu, 2 Nov 2000 10:36:23 +0100 MIME-Version: 1.0 X-Mailer: Internet Mail Service (5.5.2650.21) Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 8bit X-MIME-Autoconverted: from quoted-printable to 8bit by delorie.com id EAA02194 > klaus DOT berndl AT sdm DOT de wrote: > > > > If i start a program in the background from bash (e.g. > "winword.exe &") then > > all is working fine. But if i try to exit from the > bash-shell from which i have started the program > > before i have finished the program then bash writes > "logout" but doesn´t terminate until i terminate > > all previous started programs. > > > > How can this be avoided, means how to exit bash regardless > of any still running background programs? > > Never, I fear. It sounds as if you are running some 9X system. It's > a problem of all 9X console windows that you can't close the window > unless all child processes are killed. If you want to run daemons > invisible you'll have to start them by using a shortcut with the > minimized state set. No, im using Windows NT!! -- Want to unsubscribe from this list? Send a message to cygwin-unsubscribe AT sourceware DOT cygnus DOT com