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From: "Noel L Yap" <yap_noel AT jpmorgan DOT com>
To: cygwin AT sources DOT redhat DOT com
Message-ID: <8525692A.00642773.00@nyc-ntgw-n01.ny.jpmorgan.com>
Date: Fri, 28 Jul 2000 14:13:58 -0400
Subject: Re: shell script bug
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cgf AT cygnus DOT com on 2000.07.28 12:57:49
>On Fri, Jul 28, 2000 at 09:30:13AM -0700, Noel Yap wrote:
>>I have the following script asdf.sh:
>>#!/bin/sh
>>
>>if [ $# = 1 ]
>>then
>>  for v in "$@"
>>  do
>>    echo $# should be 1
>>    echo "$v"
>>  done
>>else
>>  for v in "$@"
>>  do
>>    echo $# isn\'t be 1
>>    ./asdf.sh "$v"
>>  done
>>fi
>>
>>Under bash, the output of the script is:
>>5 isn't 1
>>5 isn't 1
>>5 isn't 1
>>5 isn't 1
>>5 isn't 1
>>
>>Under sh, there is no output.
>
>...which is what I'd expect.

Why?  From what I've read in "Unix Shells by Example" on page 259:
$@   Means the same as $*, except when enclosed in double quotes.  BTW, my
command line was:
./asdf.sh "a b" 'c d' e\ f g h

>I tried this on a couple of machines and the behavior is inconsistent.
>Some print "0 isn't be 1" (sic) and some print nothing.
>
>I would consider the triggering of the for-loop when there are no
>arguments supplied to the shell script to be a bug.

I agree, but I'm not seeing that behaviour.

Noel




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