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Date: Thu, 15 Jul 1999 21:23:34 -0400
From: Joshua Rosen <rozzin AT geekspace DOT com>
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To: cygwin AT sourceware DOT cygnus DOT com
Subject: Re: bash: pushd
References: <Pine DOT BSF DOT 4 DOT 05 DOT 9907160230050 DOT 15929-100000 AT mail DOT kolej DOT mff DOT cuni DOT cz> <378E8172 DOT 42692CCB AT dgs DOT monash DOT edu DOT au>
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Brendan Simon wrote:
> 
> It seems that pushd is not in the path when you run your script.
> Try putting "echo $PATH" in your script to see what the path is set to
> when the script is exectued.

`pushd' is a BASH built-in command, though--not an external programme,
so the value of $PATH shouldn't matter, so long as you're getting
bash.

Oh! I've solved it--
Note that, if I do

echo foo > a

`./a' gives `foo: not found'. Also note that *./a is not listed as
being executable*.

If we do this, however:

echo '#!'"$(type -p sh)
foo
" > b

..., then we note that `./b' will actuall run `foo', and spit out
whatever the result of doing so is. We also notice that `ls -l b'
shows b as executable!:)

If you do run into problems with the $PATH or some other variable not
being correctly known by a shell script, use `env', ie: check the
output of this:

echo '#!'"$(type -p env) sh
pushd foo
"

Direct said output into a file, find that Cygwin recognises the file
as being executable (because of the hashbang), and `pushd foo' (or
whatever else is there) is executed with the current environment,
after `sh' is found in the current PATH.


		-Rozzin.

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