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Subject: Re: pipe broken by WSL?
To: cygwin@cygwin.com
References: <2a6d7c3d-f8ff-eafe-3048-8bbd689216c5@towo.net> <20190502153726.GA1867@zebra> <a2cc9af3-eb31-8b7d-e3f4-fa3e2f21cd40@cs.umass.edu>
From: Thomas Wolff <towo@towo.net>
Message-ID: <4c5ab3a4-7fec-bbf5-adb6-87a219dbe0b2@towo.net>
Date: Fri, 3 May 2019 04:32:27 +0200
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Am 02.05.2019 um 18:26 schrieb Eliot Moss:
> On 5/2/2019 11:37 AM, Stephen Carrier wrote:
>> On Wed, May 01, 2019 at 11:20:59AM +0200, Thomas Wolff wrote:
>>> Calling WSL seems to break pipe processing:
>>>
>>> (echo 1; echo 2) |
>>> while read line
>>> do
>>>    echo $line
>>>    wsl uname
>>> done
>>
>> I don't know about wsl, but could it be absorbing the standard input?
>> What if "wsl uname" is replaced with "wsl uname < /dev/null" ?
>
> You seem to be right; when I add < /dev/null as described, I get the 
> expected output.
Yes, indeed. Thanks.
Thomas
>
> Regards - Eliot
>
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