Subject: Re: scanf "%n" format specifier is not supported
From: [email-masked] ($Bill Luebkert)

23 Jun 1998 03:34:46 -0700
Message-ID: <[email-masked]>
References: <Pine.GSO.3.96.980622162749.14664D-100000@sigma>
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To: "[email-masked]" <[email-masked]>

Alexander Chernov wrote:
> 
> Hello,
> 
> This looks like a missing feature: "%n" format specifier in sscanf
> is not supported. For example, the following piece of code
> left variable n value as 0 instead of 2. According to my textbooks
> ANSI C specifies %n specifier.
> 
> #include <stdio.h>
> #include <string.h>
> 
>   int
> main()
> {
>   int v = 0, n = 0, r = 0;
> 
>   r = sscanf("32", "%d %n", &v, &n);
>   printf("v = %d\nn = %d\nr = %d\n", v, n, d);
>   return 0;
> }

I would assume this is normal behavior since the %d sucked up the entire 
"32" and left nothing for the %n.

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