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References:	<202310100335 DOT 39A3Zn6W3486400 AT envy DOT delorie DOT com> <ZSbQU1dZl5qEadSV AT camus>
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From:	"Alex Natalsson (svetonomer AT gmail DOT com) [via geda-user AT delorie DOT com]" <geda-user AT delorie DOT com>
Date:	Wed, 11 Oct 2023 20:30:24 +0300
Message-ID:	<CAG4ve9+Ve=EUZ=gwNxvfCeo4zFUHgb_Qxzo_uo-wfkiV8vJ8mQ@mail.gmail.com>
Subject:	Re: [geda-user] is geda dead yet?
To:	geda-user AT delorie DOT com
Reply-To:	geda-user AT delorie DOT com

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>
> Hi DJ,
>
>
> It's not clear what direction this thread is going -- it has discussion
> of forks, plenty of users, but nobody stepping up as developers -- so in
> case it leads to the list or project shutting down, I just wanted to say
> thank you.
>

Yes, Geda is a good program, I really like it and I also once did a bit for
it. And I join to "Thank you."
It's a shame when projects like this can close down. It's like Python2, I
still write in it, but it works. Sometimes you just need to do something. I
couldn't launch Geda to run, and I found a fork. When a project is not
developing, but at the same time it has many working forks, this says
something. It's need to understand what this means. If, of course, the
developers are interested.

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<div dir=3D"ltr"><div class=3D"gmail_quote"><blockquote class=3D"gmail_quot=
e" style=3D"margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204)=
;padding-left:1ex">Hi DJ,<br>
<br>
<br>
It&#39;s not clear what direction this thread is going -- it has discussion=
<br>
of forks, plenty of users, but nobody stepping up as developers -- so in<br=
>
case it leads to the list or project shutting down, I just wanted to say<br=
>
thank you.<br></blockquote><div>=C2=A0</div><div>Yes, Geda is a good progra=
m, I really like it and I also once did a bit for it. And I join=C2=A0to &q=
uot;Thank you.&quot;</div>It&#39;s a shame when projects like this can clos=
e down. It&#39;s like Python2, I still write in it, but it works. Sometimes=
 you just need to do something. I couldn&#39;t launch Geda to run, and I fo=
und a fork. When a project is not developing, but at the same time it has m=
any working forks, this says something. It&#39;s need to understand what th=
is=C2=A0means. If, of course, the developers are interested.</div></div>

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