delorie.com/archives/browse.cgi | search |
X-Authentication-Warning: | delorie.com: mail set sender to geda-user-bounces using -f |
X-Recipient: | geda-user AT delorie DOT com |
DKIM-Signature: | v=1; a=rsa-sha256; c=relaxed/relaxed; |
d=gmail.com; s=20120113; | |
h=mime-version:date:message-id:subject:from:to:content-type; | |
bh=IejcKr2UM4vhWRUZtlYUuSJRGLZpO81cpuXQUQKjRG8=; | |
b=PViGOENzKgUs8PiXnIRB8GLHj3Qb3Bt0jcsEEQD0qiyFdq45OfuLl5RyjQ4JhZ/kWr | |
+a4hCRyF88NR+PcZMU/Bgz/f21tcalHhXHkmpT9m+9oEu+I+2Et8mKc5KIjxTB4wpNVM | |
1ccoBI/rp8rqDMzo90Z5TXeE+dMDUk3mkClJP0oMkC9SfTCkkRKWikqz+1WnXv5eoDZy | |
N+7lD6c9DWuzMboVZ3SMJVYFTin+rRTfcQlnlvsWaXj8pSQ995GQU/LA/y7LeUMtJOis | |
jkIbfNRSFpBiNDfr9oD12tMlS6IKLl5YMuCa94FnIV6cLOplFrMZsV6H0w3GwVJdQDRo | |
2ndw== | |
MIME-Version: | 1.0 |
X-Received: | by 10.220.64.69 with SMTP id d5mr40780771vci.11.1388517984207; |
Tue, 31 Dec 2013 11:26:24 -0800 (PST) | |
Date: | Tue, 31 Dec 2013 14:26:24 -0500 |
Message-ID: | <CALSZ9go-H-4HnAfvdQyLsVEcbNG0pT33wEM=G-CfZmDXVcMQrw@mail.gmail.com> |
Subject: | [geda-user] Help sending a sine wave to a speaker |
From: | Rob Butts <r DOT butts2 AT gmail DOT com> |
To: | geda-user AT delorie DOT com |
Reply-To: | geda-user AT delorie DOT com |
--089e010d97303689d404eed98910 Content-Type: text/plain; charset=ISO-8859-1 It has been a while since I've written major C code so I'm having a hard time coming up with the code. I have a simple design where I use a microchip pic16f1825 to read a byte from an eeprom via spi and send it to a dac and ultimately to a speaker. As a dac and speaker test I want to send a simple 1000Hz sine wave to the dac at an 8KHz rate. Can anyone check my thoughts below? Here's my thinking... If I set my timer to interrupt at an 8KHz rate and if I want to play the tone for 10 seconds the for loop might look something like this: for(j=0; j < 80000; j++){ // j is the sample index // straight sine function means one cycle per 2*pi samples // sample(j) = sin(j) // multiply by 2*pi now it is one cycle per sample // sample(j) = sin((2 * pi) * j) // multiply by 1,000 samples per second now it is cycles per second // sample(j) = sin(1000 * 2 * pi * j) // divide by 8000 samples per second now it is cycles per 8000 samples // sample(j) = sin(1000 * 2 * pi * j / 8000) // the 1000 cycles is the frequency so in those terms // sample(j) = sin(freq * 2 * pi * j / 8000) // now if I want to normalize the amplitude to 0xff the final value is // sample(j) = 0xff * sin(freq * 2 * pi * j / 8000) // so... declaring sample as a float sample = 0xff * sin(freq * 2 * pi * j / 8000); while(!update_dac){ // where update_dac is set to 1 in the timer interrupt handler } update_ dac = 0; send_dac((UINT8) sample); } When I execute the code and step through it the value for sample when j = 1 is 180.238where I expect 3.146 Can someone see my error or what is going on? Thanks --089e010d97303689d404eed98910 Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable <div dir=3D"ltr"><div>It has been a while since I've written major C co= de so I'm having a hard time=20 coming up with the code. <br></div><div>I have a simple design where I use = a microchip=A0pic16f1825 to=20 read a byte from an eeprom via spi and send it to a dac and ultimately to a= =20 speaker.=A0 As a dac and speaker test I want to send a simple 1000Hz sine w= ave to=20 the dac at an 8KHz rate.=A0<br>=A0=A0=A0 <br>Can anyone=A0check my thoughts= below?=A0 Here's my thinking... <br>If I=20 set my timer to interrupt at an 8KHz rate and if I want to play the tone fo= r 10=20 seconds the for loop might look something like this: <br>=A0 <br>for(j=3D0;= =A0j <=20 80000; j++){ <br>=A0=A0=A0=A0 //=A0j is the sample index <br>=A0=A0=A0 // s= traight sine function=20 means one cycle per 2*pi samples <br>=A0=A0=A0 //=A0sample(j) =3D sin(j) <b= r>=A0=A0=A0 //=20 multiply by 2*pi now it is one cycle per sample <br>=A0=A0=A0 // sample(j) = =3D sin((2 *=20 pi) * j) <br>=A0=A0=A0 // multiply by 1,000 samples per second now it is cy= cles per=20 second <br>=A0=A0=A0 // sample(j) =3D sin(1000 * 2 * pi * j) <br>=A0=A0=A0 = // divide by 8000=20 samples per second now it is cycles per 8000 samples <br>=A0=A0=A0 // sampl= e(j) =3D=20 sin(1000 * 2 * pi * j / 8000) <br>=A0=A0=A0 // the 1000 cycles is the frequ= ency so in=20 those terms <br>=A0=A0=A0 //=A0 sample(j) =3D sin(freq * 2 * pi * j / 8000)= <br>=A0=A0=A0 // now=20 if I want to normalize the amplitude to 0xff=A0 the final value is <br>=A0= =A0=A0 //=20 sample(j) =3D 0xff * sin(freq * 2 * pi * j / 8000) <br>=A0=A0=A0 // so...= =A0=A0=A0=A0declaring=20 sample as a float <br>=A0=A0=A0 sample =3D 0xff * sin(freq * 2 * pi * j / 8= 000); <br>=A0=A0=A0=20 while(!update_dac){=A0=A0=A0 // where update_dac is set to 1 in the timer i= nterrupt=20 handler <br>=A0=A0=A0 } <br>=A0=A0=A0 update_ dac =3D 0; <br>=A0=A0=A0 send= _dac((UINT8) sample);=20 <br>}=A0<br>=A0 <br>When I execute the code and step through it the value f= or sample=A0when j =3D 1 is 180.238where I expect 3.146</div><div>=A0</div>= <div>Can someone see my error or what is going on?</div><div>=A0</div><div>= Thanks</div> </div> --089e010d97303689d404eed98910--
webmaster | delorie software privacy |
Copyright © 2019 by DJ Delorie | Updated Jul 2019 |