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From: | Cesar Rabak <csrabak AT yahoo DOT com DOT br> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: calling a RM function which is placed below 1 MB |
Date: | Fri, 25 Jul 2008 17:29:06 -0300 |
Organization: | Aioe.org NNTP Server |
Lines: | 22 |
Message-ID: | <g6dcq5$p6d$1@aioe.org> |
References: | <ca0df607-1be3-4358-b84f-f0ccddde3197 AT d77g2000hsb DOT googlegroups DOT com> <g67uat$di0$1 AT aioe DOT org> <f78b8a9f-b3ff-4ab6-b95b-151c822873f7 AT b1g2000hsg DOT googlegroups DOT com> <g6ath6$1lm$1 AT aioe DOT org> <8fceb180-5d7a-45e8-a585-0d001b3ba089 AT 1g2000pre DOT googlegroups DOT com> |
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To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
Eph escreveu: > Hey again, > > I think, it got confused everything :). So I try to start over. > > So. I have a function which waits in the memory below 1MB. This > function awaits parameter on the stack at [06], [10] a. [14]. > This function must be called from 16Bit RM. How should I do this? > I found the function > __dpmi_simulate_real_mode_procedure_retf_stack(...) which I think is > the right one for my problem. > But how do I create the stack parameter and the regs? > The segment and offset of the function entry is known. The parameters > too. I just need to know how to call the function correctly or if > someone knows a better way to do this I would be glad too!! > Eph, First of all: have you a sample of the successful call to this function in ordinary real mode assembly?
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