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Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: system() return value if no program present |
Date: | Fri, 01 Oct 2004 12:37:33 +0200 |
Organization: | Telefonica Data Espagna |
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Eli Zaretskii escribió: >>>>When executed in my system I find myself in a new shell: >>>> >>>>Microsoft Windows XP [Versin 5.1.2600] >>>>(C) Copyright 1985-2001 Microsoft Corp. >>>> >>>>c:\c> >>> I have found the same problem in another computer and I have found that this only happens when an environment variable "SHELL" is defined. If I undefined it, no interactive shell is launched. set SHELL= - system("grep")=2 and works as expected - system("notexist")=0 and works as expected ("not found") - system("dir")=0 and works as expected set SHELL=cmd - system("grep")=2 and works as expected - system("notexist")=-1 and works as expected ("not found") - system("dir")=-1 and it does nothing (¿why?) set SHELL=c:\wtsrv\system32\cmd.exe (correct path) - system("grep")=2 and works as expected - system("notexist") runs interactive shell and then returns 0 (¿why?) (this was what begun my question) - system("dir") runs interactive shell and then returns 0 (¿why?) Thank you
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