From:	Richard Dawe <rich AT phekda DOT freeserve DOT co DOT uk>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: displaying numbers in hexadecimal
Date:	Sat, 05 Oct 2002 18:31:56 +0100
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To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

Hello.

John Smth wrote:
> How can i get my program to display a number in hexadecimal form? For
> example, in my program i have a line cout << 0x9 + 0x2 << "\n";
> the output is 11, but i need t to be 'B'. It was suggested to me to add
> '<<hex<< to the line but the compiler didnt recognize the 'hex' command.

Try:

    cout << hex << (0x9 + 0x2) << endl;

You may want to switch the default number format back to decimal, after
switching it to hexidecimal:

    cout << hex << (0x9 + 0x2) << dec << endl;

HTH. Regards,

-- 
Richard Dawe [ http://www.phekda.freeserve.co.uk/richdawe/ ]

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