Message-ID:	<3BC16F90.A6FE66E3@falconsoft.be>
Date:	Mon, 08 Oct 2001 11:19:12 +0200
From:	Tim Van Holder <tim DOT vanholder AT falconsoft DOT be>
Organization:	Anubex (www.anubex.com)
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Subject:	Re: More out from "cout"....
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Traveler wrote:
> 
> 
> template <int n>
> ostream&    operator<<(ostream& output,int (&table)[n])
> {
>     unsigned long    length = sizeof(table)/sizeof(table[0]);

Since you know the type here, you culd use sizeof(int) instead
of sizeof(table[0]).
Of course, since you also know the array is of length n, this
entire construct is superfluous.

>     for(unsigned long index = 0;index < length;index++)
>        output << '[' << table[index] << ']';

Hmm - I'm not sure I want array elements shown inside [].
A more logical way to do it is to separate them by ", ".
Also, you can probably templatize the array type as well.

template <typename T, size_t N>
ostream&
operator<<(ostream& out, T (&array)[N])
{
  for (size_t i = 0; i < n; ++i) {
    if (i > 0)
      out << ", ";
    out << array[i];
  }
  out.flush();
}


Of course, if you're going to screw around with templates,
you really should be using STL vectors instead:

template <typename T, typename A>
std::ostream&
operator<<(std::ostream& out, const std::vector<T, A>& array)
{
std::vector<T, A>::const_iterator first = array.begin();
std::vector<T, A>::const_iterator last  = array.end();
std::vector<T, A>::const_iterator i;
  for (i = first; i != last; ++i) {
    if (i != first)
      out << ", ";
    out << (*i);
  }
  out.flush();
}

or something like it anyway (not sure if this function needs
to include the allocator used by the vector as template arg).

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