From:	"Chris Van Extergem" <chris DOT ve AT pandora DOT be>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Deriving from class streambuf
Lines:	45
X-Priority:	3
X-MSMail-Priority:	Normal
X-Newsreader:	Microsoft Outlook Express 5.00.2919.6600
X-MimeOLE:	Produced By Microsoft MimeOLE V5.00.2919.6600
Message-ID:	<n6uP6.2496$X03.195337@afrodite.telenet-ops.be>
Date:	Fri, 25 May 2001 14:37:07 GMT
NNTP-Posting-Host:	213.224.14.209
X-Complaints-To:	abuse AT pandora DOT be
X-Trace:	afrodite.telenet-ops.be 990801427 213.224.14.209 (Fri, 25 May 2001 16:37:07 MET DST)
NNTP-Posting-Date:	Fri, 25 May 2001 16:37:07 MET DST
Organization:	Telenet Internet
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

I copied some code from a book, it compiles and (kinda) works with VC++ 6.0,
but when I want to compile with DJGPP, I get following error :

winstream.cpp(8) Error: no matching function for call to
'streambuf::streambuf(char *&, winstrbuf::{anonymous enum})

on this line :

winstrbuf::winstrbuf(int y,int x,int h,int w,int bx,int
vis):streambuf(pbuf=new char[bufsize*2],bufsize),curw(y,x,h,w,bx,vis)

I know where the winstrbuf::{anonymous enum} part comes from :
    enum {bufsize=1024}; in my class declaration, so that's not a problem, I
guess

When I look at streambuf.h, I can only find one constructor for streambuf :
    streambuf(int flags=0);

When I look at streamb.h (for VC++ 6.0), I find :
    streambuf();
    streambuf(char *,int);

So that explains why it compiles in VC++ 6.0

My question (at last, I hear you say :) is this : who is right ? I know M$
is known for producing the least conforming compiler, but here it seems the
author of DJGPP got a bit lazy and left out the second constructor.  Does
the standard say anything about this ?
Should I add this constructor myself ? Should I just adjust my code ? If
yes, how ?

--

TIA

Chris


--

TIA

Chris

- Raw text -