From:	"Rafael García" <rafael AT geninfor DOT com>
Newsgroups:	comp.os.msdos.djgpp
Subject:	atoi() with 8 bit chars
Date:	Wed, 28 Feb 2001 14:09:30 +0100
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To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

Hello all. I have found a bug in one of my functions due to an extrange
behaviour of atoi() with bad data introduced by a user in a date. If you
give 8-bit chars to atoi, it does not return cero. Does anybody know why?

#include <stdio.h>
#include <stdlib.h>

int main() {
   int n;
   char s1[]="?";
   char s2[]="?0";

   for (n=0;n<=255;n++) {
      printf("%d:\t",n);
      s1[0]=n;
      printf("atoi(\"%s\")=%d\t",s1,atoi(s1));
      s2[0]=n;
      printf("atoi(\"%s\")=%d\n",s2,atoi(s2));
      }
   return 0;
   }

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