Date:	Fri, 09 Feb 2001 12:30:05 +0200
From:	"Eli Zaretskii" <eliz AT is DOT elta DOT co DOT il>
Sender:	halo1 AT zahav DOT net DOT il
To:	rpolzer AT web DOT de (Rudolf Polzer)
Message-Id:	<9791-Fri09Feb2001123005+0200-eliz@is.elta.co.il>
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CC:	djgpp AT delorie DOT com
In-reply-to:	<slrn987a3t.qp.rpolzer@rebounce.rpolzer-lx>
Subject:	Re: what does the -s switch do?
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> From: rpolzer AT web DOT de (Rudolf Polzer)
> Newsgroups: comp.os.msdos.djgpp
> Date: Fri, 9 Feb 2001 09:21:17 +0100
> 
> I forgot to ask,
> is "gcc -O3 -ggdb3 -o X.EXE" and then "strip -s X.EXE" equivalent to
> leaving out -ggdb3?

No.  "strip foo.exe" (note: no -s switch to strip) is actually _more_
than just leaving out -ggdb3.  -ggdb3 adds line number and other
source-related information, but a minimal set of information about
symbols is put into the binary even without -g.  `strip' removes _all_
of the symbolic info, leaving just the bare machine code.

For example, without -ggdb3 you should still be able to run SYMIFY and
get at least the functions' names from the addresses.  After `strip',
this is impossible.

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