From:	"Alexei A. Frounze" <dummy_addressee AT hotmail DOT com>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: How I can get 32Bit code with gcc?
Date:	Sun, 21 Jan 2001 12:16:09 -0500
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You really get 32-bit code. The problem is that your disassembler assumes
the code to be 16-bit and disassembles it in 16-bit manner. 32-bit and
16-bit instructions are very often encoded using the same sequences of
op-codes, so unless the disassembler knows whether or not the code is 32-bit
it may make a wrong dump.

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Alexei A. Frounze
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"Christian Merz" <cmerz AT bndlg DOT de> wrote in message
news:94ehvn$350$1 AT snoopy DOT bndlg DOT de...
> I have following problem with gcc. If I compile and link, for example the
> following code with "gcc -c main.c -o
> main.o -nostdlib -fno-builtin -nostartfiles -Di586" and "ld -o
> main.com -oformat binary -T startup\link.scr startup\c1.o main.o" (c1.o is
> my on startup code).
>
> /*main.c*/
> int main() {
>    for(;;);
>    return 0;
> }
>
> i'll get somthing like that, if I take a look with the dos debug.exe:
>
> 0x100: pusb bp
> 0x101: mov bp,sp
> 0x103: nop
> 0x104: jmp  0x104
> 0x106: mov si,si
> 0x109: xor ax,ax
> 0x10c: jmp 0x10f
> 0x10f: leave
> 0x110: ret
>
> but this is not what i want, i want such a thing like this:
>
> push ebp
> mov ebp,esp
> nop
> .
> .
> .
>
> I have no idea whats going wrong here, but i need the 32bit code! More I
> need a output file with 32bit segments too (flat memory stuff)!
>
> Anybody has an idea, how i'll get this simple thing running?
>
> thanks in advance
>
> chris
>
>

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