Message-ID:	<006101c06103$dc9dd020$aa4d57cb@spunky>
From:	"JB" <jamesb AT northnet DOT com DOT au>
To:	<djgpp AT delorie DOT com>
References:	<3a30b1a8$0$24264 AT diablo DOT uninet DOT ee>
Subject:	Re: Help! function typedef
Date:	Fri, 8 Dec 2000 21:44:36 +1100
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Reply-To:	djgpp AT delorie DOT com

typedef int MY_FUNC_TYPE;

MY_FUNC_TYPE func(void)
{
    return 0;
}

But it looks as if you were looking for a pointer to a function, in which
case you could do this:

typedef int (* MY_FUNC_TYPE)(void);

MY_FUNC_TYPE = my_func;

... call it like this:
MY_FUNC_TYPE();

int my_func(void)
{
    return 0;
}

Another example:

struct func_struct {
    void (* say_something)(char *);    /* pointer to function that takes a
char pointer and returns NULL */
    int (* some_function)(int, int);    /* takes 2 ints and returns their
product */
} func_structure;

int main(int argc, char **argv, char **envp)
{
    struct func_structure f_struct;
    int ival;
    f_struct.say_something = hello;
    f_struct.some_function = product;
    f_struct.say_something();
    ival = f_struct.some_function(5, 10);
    printf("ival = %d\n", ival);
    return 0;
}

void hello(char *str)
{
    printf("%s\n", str);
}

int product(int i, int j)
{
    return i * j;
}

----- Original Message -----
From: "Tonu Aas" <tonu AT ids DOT ee>
Newsgroups: comp.os.msdos.djgpp
To: <djgpp AT delorie DOT com>
Sent: Friday, December 08, 2000 8:55 PM
Subject: Help! function typedef


> Why doesnt this work ?
>
> typedef int (MY_FUNC_TYPE)(void);
>
> MY_FUNC func
>  {
>   return 0;
>  }
>
> Error: syntax error before `{'
>
> Tõnu.
>
>

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