Date:	Mon, 11 Sep 2000 01:08:00 +0200
From:	Egon Eckert <egon AT chance DOT cz>
To:	djgpp AT delorie DOT com
Subject:	Re: strdup() with delete[]
Message-ID:	<20000911010800.C23829@chance.cz>
References:	<8pgtns$sja$1 AT info DOT cyf-kr DOT edu DOT pl>
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In-Reply-To:	<8pgtns$sja$1@info.cyf-kr.edu.pl>; from r_maj@poczta.onet.pl on Sun, Sep 10, 2000 at 11:18:07PM +0200
Reply-To:	djgpp AT delorie DOT com
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Err, I did quote your text wrong in my previous reply.  So, once again. :)

> All memory allocated like
>   char* s = new char[100];
> should be deleted using :
>   delete s[];
> right ?

I guess the [] form is considered obsolete.  I would use simple delete s. 
The operator's implementation knows how many objects are allocated.

> And what about allocation done with strdup() :
>   char* s = strdup("test");
> should I use then delete s[];  OR  delete s;  ?

I would call free here (see my previous mail).

> =============
> Is this correct :
>     char *s;
>      if (/*...*/) s=strdup(S);  else  { s=new char[2];  s[0]=ch;
>  s[1]=NULL; }
>     delete s[];

It doesn't make big difference in this case (free or delete), I think using
both is safe here.  Delete performs 'destruction' of all the objects, which
means nothing for 'char'.  One recommendation: I would use

s [1] = 0;

instead of 's [1] = NULL;'.  NULL is a hint for "pointer" value, but you
assign 'char' in this case, no pointer.

BTW: I'm not sure whether it's recommended to use NULL at all in 'modern'
C++, shouldn't we use simply '0' everywhere instead of NULL?

-- 
Egon Eckert, Chance, a.s.
E-mail: egon AT chance DOT cz

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