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X-Originating-Host: | 202.137.2.145 |
Organization: | http://www.remarq.com: The World's Usenet/Discussions Start Here |
Subject: | Re: multitasking/threading in DJGPP |
Lines: | 33 |
From: | batchex <thedark1NOthSPAM AT phreaker DOT net DOT invalid> |
Newsgroups: | comp.os.msdos.djgpp |
Message-ID: | <07e97600.58b5dac5@usw-ex0101-005.remarq.com> |
References: | <Pine DOT SUN DOT 3 DOT 91 DOT 1000619173815 DOT 27216T-100000 AT is> <394F7CEF DOT C3B04F13 AT crosswinds DOT net> <200006202002 DOT XAA00101 AT alpha DOT netvision DOT net DOT il> <3951E3E6 DOT 34B80384 AT crosswinds DOT net> |
Bytes: | 1202 |
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Date: | Mon, 26 Jun 2000 13:32:24 -0700 |
NNTP-Posting-Host: | 10.0.2.5 |
X-Complaints-To: | wrenabuse AT remarq DOT com |
X-Trace: | WReNphoon4 962051682 10.0.2.5 (Mon, 26 Jun 2000 13:34:42 PDT) |
NNTP-Posting-Date: | Mon, 26 Jun 2000 13:34:42 PDT |
To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
Hi, I am now thinking on how to destroy a thread when it finished it's job. My original idea is to write a multithreaded lib to support more than one functions to execute concurrently. I have no intentions, at least not now, to support different programs to execute concurrently. The idea is to call a spawn_thread() function to setup a new thread, which is actually another function running in paralel with the main program. What I'm confused with when that function returns, how can I detect this and how to clean up the mess. One way to do this IMO is by using a job_done flag and end_thread () function which have a pseudo-code like this : 1. set this thread's job_done flag to true 2. enter an infinite loop end_thread() is called at the end of a thread function. It's the scheduler job to check the job_done flag for every thread and if it finds a thread with a true flag, then do the necessary cleanup. Plz tell me what you think. BTW, my questions regarding a comprehensive signals guide and how to determine the source of a signal still stands. Thanks Got questions? Get answers over the phone at Keen.com. Up to 100 minutes free! http://www.keen.com
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