From:	Erik Berglund <erik2 DOT berglund AT telia DOT com>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Possible truncation error
Lines:	29
Message-ID:	<_x665.15310$Za1.242989@newsc.telia.net>
Date:	Tue, 27 Jun 2000 18:39:54 GMT
NNTP-Posting-Host:	194.237.157.182
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NNTP-Posting-Date:	Tue, 27 Jun 2000 20:39:54 MET DST
Organization:	Telia Internet
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

Hi, I tried the following program, which gives
j=9999. I think the right result should be 10000,
because a=0x40c3880000000000, which is exactly 10000.

#include <stdio.h>
#include <math.h>
int main() {
double a;
int j,*p;

   a = pow(100,2);
   j = a;
   p = (int*)&a;
   printf("%08x%08x\n",*(p+1),*p);
   printf("%i\n",j);
   return(0);
}

If I insert a printf("\n") before j=a;, the result
becomes 10000 instead, and I have no idea why.

Thanks in advance,

--

Erik Berglund
erik2 DOT berglund AT telia DOT com

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