Message-ID:	<38D9500A.57750639@ou.edu>
From:	David Cleaver <davidis AT ou DOT edu>
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Newsgroups:	comp.os.msdos.djgpp
Subject:	TO: Dennis Kent
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Date:	Wed, 22 Mar 2000 16:58:18 -0600
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To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

Hello,

I tried to reply to your e-mail address but it bounced and so I thought I'd just
post to this group and hope you see the response I sent to you.  I've pasted it
below:

//=============================================
Sorry I haven't answered in a week, but I was away on Spring Break.

Ok, I just looked up the info and found out that scanf() only reads up to the
first whitespace character.
So, the function you want to use is gets() which will get everything up to, but
not including, the new-line character.  You can use it thus:


char name[41];
gets(name);
/*
The gets() function will read 40 characters from the input stream and put them
in the variable _name_.  It will then make the 41st character the null character
in order to terminate the string.  So, make sure that you allocate (num_chars +
1) spaces in your char array in order to hold what you want and what the
computer wants to hold in there.
*/

I think that should just about do it.
If you have any more questions feel free to ask, but, remember, I'm no guru, I'm
just another average programmer.  Good luck with what you want to do.

-David C.

Dennis Kent wrote:
> 
> I saw your post on comp.os.msdos.djgpp.  You quoted:
> 
> char name[40];
>  scanf("%s", &name);
> 
> I have a question about that.  This should really be simple, but it has
> been kicking me around for some time.  I'm using linux, so that may make
> a difference in how scanf() behaves.  All I am trying to do is enter a
> string with some whitespaces from the keyboard and assign it to a
> variable.  scanf() seems to stop at the first whitespace.  How can I
> accomplish this simple matter?
> 
> dennis

//=========================================

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