From:	Damian Yerrick <DONT DOT YOU DOT DAREd_yerrick AT hotmail DOT comSEND DOT SPAM>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: long double
Organization:	Pin Eight Software http://pineight.8m.com/
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NNTP-Posting-Date:	Tue, 29 Feb 2000 06:05:45 GMT
Distribution:	world
Date:	Tue, 29 Feb 2000 06:05:45 GMT
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

On 28 Feb 2000 14:02:41 -0800, Nate Eldredge <neldredge AT hmc DOT edu>
wrote:

>Basic <_basic AT yahoo DOT com> writes:
>
>> Hi!
>>  Does anyone know how to fix this? When multiplying
>> long doubles, the result is always 2. I am using DJGPP
>> 203

Are you printf()ing them with "%Lf"?

>Please post a complete, compilable example that demonstrates this.
>I'm not aware of any such bug.

I don't get a bug either.

----- NextPart: longdbl.c
// C:\SRC\DJBUGS>gcc -Wall longdbl.c -o longdbl.exe

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main(void)
{
  int fac1, fac2;
  long double ld1, ld2, ldresult;

  for(fac1 = 1; fac1 < 10; fac1++)
    for(fac2 = 1; fac2 < 10; fac2++)
    {
      ld1 = fac1;
      ld2 = fac2;
      ldresult = ld1 * ld2;
      printf("%d * %d = %Lf\n", fac1, fac2, ldresult);
    }
  return 0;
}

// Works as advertised, producing a multiplication table.

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