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Date: | Mon, 21 Feb 2000 22:49:22 +0500 (MVT) |
From: | Prashant TR <prashant_tr AT yahoo DOT com> |
X-Sender: | prashant_tr AT midpec DOT com |
To: | Nite Hawk <malcolm3 AT bulloch DOT net> |
cc: | djgpp AT delorie DOT com |
Subject: | Re: Newbies need help too! <smile> |
In-Reply-To: | <88q38n$6cf$1@news3.infoave.net> |
Message-ID: | <Pine.LNX.4.10.10002212247050.998-100000@midpec.com> |
MIME-Version: | 1.0 |
Reply-To: | djgpp AT delorie DOT com |
Errors-To: | dj-admin AT delorie DOT com |
X-Mailing-List: | djgpp AT delorie DOT com |
X-Unsubscribes-To: | listserv AT delorie DOT com |
On Sun, 20 Feb 2000, Nite Hawk wrote: > 1. when I try to divide "taxPercent/100" it's value turns out to be "0" (I'm > dividing a whole # such as 6 by 100 to get .06) That's because you are dividing an interger by another integer. So, the result would be an integer. You need to do 6*1.0/100 to get .06. > 2. How do I get a variable to contain a name? (I'm trying to get a name as a > variable, is this possible?) char yourName[100]; To store the name: strcpy(yourName, "Nite Hawk");
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