Message-ID:	<384A10E5.E5BD0A30@sgi.net>
From:	John & Susie <jdk AT sgi DOT net>
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Subject:	Re: Why "c" is always zero??
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Date:	Sun, 05 Dec 1999 02:14:45 -0500
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> Jason Yip wrote:
> 
> Can anyone tells me why the value of "c" is always equal to zero??
> How can I correct this?
> Thanks a lot!!
> 
> #include <stdio.h>    
                       <---- <float.h> is not declared.
> float ftc(n)         <---- you dont use the passed value 'n' in your function - 
> int n;               <-----but you declare it old style here? (the address
                             where it would be stored happened to be
zero or
                             your compiler automagicly set it to 0)?
Your compiler
                             should warn you here - dump this.
> {
> float c, f; int i;   <---- f = 0 (dont count on it, could be anything)
>  for (i=0;i<=n;i++){ <---- 'f' is not modified
>  c=5/9*(f-32);       <---- c = 5/9*(0-32) should be about -17.7777
}
> return c;    <------------ you return 'c' which should be -17.7777
                             but get 0 (didnt declare float.h,
possibly)?
> }
> main ()
> {
> float c, f=0; int i=0;
> do
> {
> c=ftc(i);
> printf("\t\t F=%.2f \t\t C=%.2f\n",f,c);
> f++;
> i++;
> } while (i<=100);
> }

Actually, trying to compile this under NT wedged Rhide.

Make some changes, use one loop, use doubles instead of floats and do
visit...

comp.lang.c.moderated
comp.lang.c

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