Message-ID:	<3849FB74.AAC74D31@armenia.multi.net.co>
Date:	Sun, 05 Dec 1999 00:43:16 -0500
From:	Jorge Ivan Meza Martinez <jimezam AT armenia DOT multi DOT net DOT co>
X-Mailer:	Mozilla 4.61 [en] (Win98; I)
X-Accept-Language:	es-CO,en
MIME-Version:	1.0
To:	djgpp AT delorie DOT com, manman AT netteens DOT net
Subject:	Re: Why "c" is always zero??
References:	<82cko6$sfk$1 AT imsp026 DOT netvigator DOT com>
Reply-To:	djgpp AT delorie DOT com

Look carefuly to your code ...

> float ftc(n)
> int n;
> {
> float c, f; int i;
>  for (i=0;i<=n;i++){
>  c=5/9*(f-32);
>         }
> return c;
> }

>  c=5/9*(f-32);
          ^

when you give a value to f ?

is garbage now.

jimezam.


> Jason Yip wrote:
> 
> Can anyone tells me why the value of "c" is always equal to zero??
> How can I correct this?
> Thanks a lot!!
> 
> #include <stdio.h>
> float ftc(n)
> int n;
> {
> float c, f; int i;
>  for (i=0;i<=n;i++){
>  c=5/9*(f-32);
>         }
> return c;
> }
> main ()
> {
> float c, f=0; int i=0;
> do
> {
> c=ftc(i);
> printf("\t\t F=%.2f \t\t C=%.2f\n",f,c);
> f++;
> i++;
> } while (i<=100);
> }

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