Mail Archives: djgpp/1999/11/01/09:28:25
| From: | "Jason News" <hello AT mymail DOT com>
|
| Newsgroups: | comp.os.msdos.djgpp
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| Subject: | Que on C
|
| Date: | Mon, 1 Nov 1999 19:54:22 +0800
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| Organization: | netteens.net (Hongkong Telecom IMS)
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| Lines: | 57
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| Message-ID: | <7vjv87$32f$1@imsp026.netvigator.com>
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| NNTP-Posting-Host: | olkc10a130.netvigator.com
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| To: | djgpp AT delorie DOT com
|
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp
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| Reply-To: | djgpp AT delorie DOT com
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This is a multi-part message in MIME format.
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Hi everyone,
can anyone tells me why
int x=3D5, y=3D5;
printf ("1st %d, 2nd %d\n" ++x, y++");
will show 1st 6, 2nd 5
int x=3D5
prinf ("1st %d, 2nd %d\n" ++x, x++");
will show 1st 7, 2nd 5
What I don't understand is that the increament of ++x is 1. Then why the =
latter one will show 7, the one with increament value 2?
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META content=3D"text/html; charset=3Diso-8859-1" =
http-equiv=3DContent-Type>
<META content=3D"MSHTML 5.00.2314.1000" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>Hi everyone,</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>can anyone tells me why</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>int x=3D5, y=3D5;</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>printf ("1st %d, 2nd %d\n" ++x, =
y++");</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>will show 1st 6, 2nd 5</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>int x=3D5</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>prinf ("1st %d, 2nd %d\n" ++x, =
x++");</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>will show 1st 7, 2nd 5</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>What I don't understand is that the =
increament of=20
++x is 1. Then why the latter one will show 7, the one with increament =
value=20
2?</FONT></DIV></BODY></HTML>
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