From:	dsk <dseeker AT pd DOT jaring DOT my>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: How to print a control-key on a file?
Date:	Sun, 03 Oct 1999 19:24:53 +0800
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To:	djgpp AT delorie DOT com
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Horst Kraemer wrote:

> On Sat, 02 Oct 1999 23:18:58 +0800, dsk <dseeker AT pd DOT jaring DOT my> wrote:
>
> > I HADDD been trying all the stuff and I still can't print control key
> > (eg ascii 10,11) to
> > a file. I got odd results in the output file.
>
> Open the file in binary mode:
>
>         fp = fopen("stuff","wb");
>         fp = fopen("stuff","rb");
>
> By default "r" and "w" open in text mode. In text mode  (char)10=='\n'
> is translated by DOS compilers to the sequence 13 10 and 13 10 are
> read back as a single (char)10=='\n'.
>
> You may read back a "text" file written "wb" even with "r". DOS
> compilers like DJGPP will treat a single 10 without preceding 13 as
> valid \n.
>
> Regards
> Horst

Yeap I tried that one but it just blow me up. I run DJGPP on WinDOSBox.
I don't know what happened but fprintf,  putc etc.. just won't work.

Is there a problem with this simple (overdefining) lines?

FILE *_outfile  =  fopen("test.zzz", "wb");
fprintf( _outfile, "%1c",  (char)10&0xFF);

Do you have hardcoding technique to stripe the 13 in front of  control key

[dsk]

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