Message-ID:	<008001bed86b$3b2f2bc0$e0023ace@alphaone>
From:	"Brian Bacon" <kyberteknik AT geocities DOT com>
To:	<djgpp AT delorie DOT com>
Subject:	Re: ANSI
Date:	Tue, 27 Jul 1999 13:04:25 -0700
MIME-Version:	1.0
X-Priority:	3
X-MSMail-Priority:	Normal
X-Mailer:	Microsoft Outlook Express 4.72.3110.1
X-MimeOLE:	Produced By Microsoft MimeOLE V4.72.3110.3
Reply-To:	djgpp AT delorie DOT com

Ok,

line 36:  missing end quote
    fprintf( stdprn, "%4d:\t%s, line++, buffer );
should be:
    fprintf( stdprn, "%4d:\t%s", line++, buffer );

line 16: fprint undeclared
    fprint f(stederr, "\nLa syntaxe correcte est: " );
should be
    fprintf(stederr, "\nLa syntaxe correcte est: " );
(fprint f  should be fprintf - no space)

and finally

line 16: stederr undeclared
    fprintf(stederr, "\nLa syntaxe correcte est: " );
should be
    fprintf(stderr, "\nLa syntaxe correcte est: " );
(stederr should be stderr - no extra 'e')


After all that I was able to successfully compile print_it.c using:
    gcc print_it.c -o print_it.exe

I did not test the program to see if it actually prints anything because I
don't have a printer and I didn't take the time to try to figure out how to
redirect stdprn.

        -Brian

    -----Original Message-----
    From: margi <margi AT club-internet DOT fr>
    To: djgpp AT delorie DOT com <djgpp AT delorie DOT com>
    Date: Tuesday, July 27, 1999 12:15 PM
    Subject: ANSI


    I'm just learning the c language with a method book, and some of the
exemple programs just can't be compilated, because of some characters like
the "\" inthe following program:

    /* PRINT_IT.C--permet d'imprimer le listings avec les num‚rots de
ligne*/
    #include <stdlib.h>
    #include <stdio.h>

    void do_heading(char *filename);

    int line, page;

    main( int argv, char *argc[] )
    {
    char buffer[256];
    FILE *fp;

    if( argv <2 )
    {
    fprint f(stederr, "\nLa syntaxe correcte est: " );
    fprintf(stderr, "\n\nPRINT_IT nomfichier.ext\n" );
    exit(1);
    }

    if (( fp = fopen( argc[1], "r" )) == NULL )
    {
    fprintf( stderr, "Erreur d'ouverture du fichier, %s!", argc[1]);
    exit(1);
    }

    page = 0;
    line = 1;
    do_heading( argc[1]);

    while( fgets( buffer, 256, fp ) != NULL )
    {
    if( line % 55 == 0 )
    do_heading( argc[1] );

    fprintf( stdprn, "%4d:\t%s, line++, buffer );
    }

    fprintf( stdprn, "\f" );
    fclose(fp);
    return 0;
    }

    void do_heading( char *filename )
    {
    page++;

    if ( page > 1)
    fprintf( stdprn, "\f");

    fprintf( stdprn, "Page: %d, %s\n\n", page, filename );
    }



    SO, PLEASE could you say me if  DJgpp is comformable to the ANSI
standard?
    and if yes, how to solve my problem, thank you

    (scuse my english, i'm french:o)

- Raw text -