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Subject:	Re: Need help with class stuff
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Message-ID:	<k9Kk3.1092$Vh.62058@wagner.videotron.net>
Date:	Mon, 19 Jul 1999 14:34:18 -0300
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To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

I know this, but now, the pointer is inside the class.
I tried it before and I get a parse error when calling the fonction  :
(ClassTest.*Action)();

Davin McCall <DavMac AT iname DOT com> a écrit dans le message :
3792ab60 DOT 19410885 AT newsserver DOT cc DOT monash DOT edu DOT au...
> Pointers to non-static member functions take a "hidden" parameter,
> which is the object on which they are to operate. So, to declare a
> pointer to a member function, you do:
>
> <return-type> (<class-name>::*<pointer-name>)(<argument-list>);
>
> for example, your:
>
> >  void (*Action)(); // my pointer
>
> Should be:   void (Test::*Action)();
>
> Davin.
> __________________________________________________________
>        *** davmac - sharkin'!! davmac AT iname DOT com ***
> my programming page: http://yoyo.cc.monash.edu.au/~davmac/

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