From:	toudi <pienkny AT friko6 DOT onet DOT pl>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Flipping an image
Date:	Wed, 14 Jul 1999 00:57:29 +0200
Organization:	beautiful piramids
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> Alan Wills wrote in message <7mf2qk$nlg$1 AT rockall DOT cc DOT strath DOT ac DOT uk>...
> >void flip_image(int array[], int rows, int cols)
> >{
> >int row_count, col_count, total_pixelsp;
> >
> >  for(row_count = 0; row_count < rows; row_count++)
> >   {
> >    for(col_count = 0; col_count < cols; col_count++)
> >     {
>
> // Something like this ? (note: this is untested)
> tmp = array[row_count * cols + col_count];
> array[row_count * cols + col_count] = array[(row_count + 1) * cols - 1 -
> col_count];
> array[(row_count + 1) * cols - 1 - col_count] = tmp;
>
> >     }
> >   }
> >}

I think you should use second array.
Your code should look like this (this is untested too):

void flip_image(int array[], int rows, int cols)
{
    int    row_count, col_count, total_pixelsp;
    int    *atmp;    // to dynamically allocate memory

    atmp = (int*)malloc(sizeof(int) * rows * cols);

    for(row_count = 0; row_count < rows; row_count++)
        for(col_count = 0; col_count < cols; col_count++)
            atmp[row_count * cols + cols - col_count] = array[row_count *
cols + col_count];
// second array is flipped in this moment

    for(row_count = 0; row_count < rows; row_count++)
        memcpy(&array[row_count * cols], atmp[row_count * cols], sizeof(int)
* cols]);
// copy second array to first array

    free(atmp);

}

Maybe there is small mistake but the idea is right.

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