Sender:	nate AT cartsys DOT com
Message-ID:	<3769510A.21F560C2@cartsys.com>
Date:	Thu, 17 Jun 1999 12:48:26 -0700
From:	Nate Eldredge <nate AT cartsys DOT com>
X-Mailer:	Mozilla 4.08 [en] (X11; I; Linux 2.2.10 i586)
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To:	djgpp AT delorie DOT com
Subject:	Re: Default File Size Blocks in Win95
References:	<3768C593 DOT 1F320E9C AT accord-soft DOT com> <3767D081 DOT 1FACAA78 AT res DOT raytheon DOT com>
Reply-To:	djgpp AT delorie DOT com

Robert W. Hazard wrote:
> 
> The short answer is:  File size / allocation of disk space is DOS / FAT
> driven which is 16 bit, and blocks are 16k.  Use or convert to a FAT32
> formatted drive (available under certain win97 installations, and win98),
> and I think they are allocated on a 4k per block basis.  Likewise for an NT
> machine and the NTFS formatting.

It's a little more complicated than that, actually; block ("cluster")
size ~= disk size / 65536, rounded up to a power of 2.  For a 2GB disk,
32K and so on upward.
-- 

Nate Eldredge
nate AT cartsys DOT com

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