From:	horst DOT kraemer AT snafu DOT de (Horst Kraemer)
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Dynamic Arrays and C++
Date:	Mon, 29 Jun 1998 14:24:56 GMT
Organization:	Unlimited Surprise Systems, Berlin
Lines:	44
Message-ID:	<35979d22.56249279@news.snafu.de>
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NNTP-Posting-Host:	n164-110.berlin.snafu.de
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

On 25 Jun 1998 18:41:06 GMT, "Brett Kugler" <w003132 AT mail DOT airmail DOT net>
wrote:

>Ok, I don't usually post here, but I've run out of options.  I've been
>trying to figure out why I'm getting an error on this line of code:

>   int *test = new int[8][8];

>The error I get is:
>	main.cpp:15: initialization to `int *' from `int (*)[8]'

>According to my C++ book (How To Program C++ by Deitel), that is a
>perfectly valid statement.

Then your C++ book is in error.

>I only have a vague notion of what the compiler
>is trying to tell me.

It is telling you that the type of 'test' and the type of 'new
int[8][8]' are not compatible.

>  I have tried:

>   int *test = new int[8];

>and this works, so it's something to do with the extra dimension in the
>array.

Yes. The expression 'new int [n1] [n2]' allocates an array of n1
objects of type int[n2]. It returns a "pointer to array of n2 ints".
This is not a "pointer to int".

The pointer the expression is assigned to has to be declared as

	int (*p)[n2];

n2 beeing a _constant_ if you want to access the allocated memory
through 'test' using the [][] syntax. Only n1 may be "variable".


Regards
Horst

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