Message-Id:	<m0yi394-000S3xC@inti.gov.ar>
Comments:	Authenticated sender is <salvador AT natacha DOT inti DOT gov DOT ar>
From:	"Salvador Eduardo Tropea (SET)" <salvador AT inti DOT gov DOT ar>
Organization:	INTI
To:	Dennis Voss <dennis DOT voss AT hamburg DOT netsurf DOT de>, djgpp AT delorie DOT com
Date:	Fri, 5 Jun 1998 17:34:48 +0000
MIME-Version:	1.0
Subject:	Re: printf bug ???
In-reply-to:	<35784752.B7BF8C31@hamburg.netsurf.de>

Dennis Voss <dennis DOT voss AT hamburg DOT netsurf DOT de> wrote:
> I just wrote this little program:
> #include <stdio.h>
> void main(void)
> {
>     int i = 1;
>     printf("%d %d %d", i, i++, i++);
> }
> Using DJGPP I got the output "3 2 1" which is wrong.
> I also compiled this with Visual C++ 5 and the output was "1 1 1".
> Can anyone help me solve this?

I don't know what ANSI standard says, but as I understand the post increment 
operator must increment after use so the right-most value will be 1 because is 
the value of i before the printf line, then gcc push the value to the stack. 
Now i *was used* and hence gcc applies the post increment so now i=2, then gcc 
pushes 2 and increments so you get 2 and 3.

SET 
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