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From: | "JAP" <jap AT mundivia DOT es> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Help about INT 21H under inline asm |
Date: | Wed, 4 Feb 1998 00:04:26 +0100 |
Organization: | Unisource Espana NEWS SERVER |
Lines: | 13 |
Message-ID: | <6bg3tt$71q$1@talia.mad.ibernet.es> |
NNTP-Posting-Host: | ninfovia180.mundivia.es |
To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Hi. I tried to call the int 21H under inline asm from gcc and i got the program fall. It caused an internal protection fault under win95. I want to know if it can be possible to call this interrupt or it's impossible under protected mode. Another question is if these lines is correct: movw $0x7, %%ax; shl $8, %%ax; because I can't make anything with AH and I wonder I I can shift 8 bits to the left and then AH=7 and AL=0 after I make the shift. Lot of thanks.
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