Mail Archives: djgpp/1997/08/31/03:25:42
|From: ||Kevin Dickerson <kevind AT phs DOT mat-su DOT k12 DOT ak DOT us>
|Subject: ||String formatting problems
|Date: ||Wed, 27 Aug 1997 05:25:16 -0800
|Organization: ||Internet Alaska Inc.
|To: ||djgpp AT delorie DOT com
|DJ-Gateway: ||from newsgroup comp.os.msdos.djgpp
I'll just be abrupt. My problem is that I am attempting, rather
unsucessfully, to write a simple text-wrapper. Nothing fancy, just
something that will pump out the text in a big poofy font. (don't ask.
:-) But anyway, the theory is that I pass a string to function
drawDialogue(char *text), and the function takes char *text and
manipulates it fairly simply. It *should* read each character, split it
up into words (seperated by spaces), and then checking the length of the
current line+length of unwritten word, making sure the text doesn't go
out of bounds of the 30 character limit (hey--it's a poofy font :-),
then does the nessessary tasks. Now, my code is fairly rudimentary right
now, so it's pretty small.
Really, my problem lies within a very narrow position, and I can't debug
it because it goes so far as to re-boot my system when I call this
stupid func! Argh. Oh, and sorry if this message seems vague or
erroneous, but I haven't been to sleep in roughly 28 hours. Bad habits
are hard to break, I suppose. :-)
(BTW, text = "Holy crap! This thing actually works! Wow! Amazing!")
void drawDialogue(char *text)
int l1, nwords, len;
char *chr, *words; // that would be one freakin' huge dialog
// This is the problem block:
for (l1=0; l1 < strlen(text); l1++) // processes text
sprintf( chr, "%c", text[l1] ); // prints the scanned character
to string chr
strcat( words[nwords], chr ); // and this line *should*, but
doesn't concatenate the character
// ...on to the word currently
being added to.
if ( text[l1] == ' ' ) // and if the processed
character is a space, then...
nwords++; // move the word up. The
checking-of-the-bounding-box isn't really
} // imperitive, because I've
localized the bug to these commands.
"nwords" is a variable containing the current word that chr will be
"words" is an array of strings that contain words (fairly obvious,
"l1" is the for(...) variable.
"chr" is a buffer containing the string format of the character being
read out of *text.
Truth be told, I've worked with just about everything *but* string
manipulation in C, so I'll probably appear fairly inept at it. I worked
on this problem of formatting the text for many, many hours without
finding any really efficient way to do it. Then I decided that I could
try to make a replica of the 30-character box in Perl (using text
instead of a graphic font), and I finished that in about 3 minutes. They
only real difficulty is figuring out how to efficiently seperate a line
of text into words. In Perl, I just used the command
"@text = split / /, $text" which, if you are familiar with Perl,
seperates $text every time it encounters a space into an array of words,
contained in @text. Argh! It's so easy in Perl, but has given me so much
greif (or is that grief?) in C. Geesh... And as usual, thanks in advance
for your help!
kevind AT phs DOT mat-su DOT k12 DOT ak DOT us
Webmaster, Palmer High School
Even webmasters get stumped. :)
- Raw text -