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Date: | Thu, 30 Jan 1997 09:39:08 +0000 |
From: | Bill Currie <billc AT blackmagic DOT tait DOT co DOT nz> |
Subject: | Re: assembler question |
To: | markiv AT rangenet DOT com |
Cc: | nikki AT gameboutique DOT co, djgpp AT delorie DOT com |
Reply-to: | billc AT blackmagic DOT tait DOT co DOT nz |
Message-id: | <32F06C3C.265E@blackmagic.tait.co.nz> |
Organization: | Tait Electronics NZ |
MIME-version: | 1.0 |
References: | <5cltef$2l1 AT flex DOT uunet DOT pipex DOT com> <32EEE110 DOT 20FC AT rangenet DOT com> |
Dan Hedlund wrote: > > try : movw (,%%ebx,2),%%ax > Better: movw (%%ebx.%%ebx,1),%%ax Omitting the base register requires an offset (1 or 4 extra bytes) which can (if I'm not mistaken) cause pairing problems on a pentium if the %ax register is replaced with a constant (and the operand reversed of course). Bill -- Leave others their otherness.
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