From:	Thomas Demmer <demmer AT LSTM DOT Ruhr-UNI-Bochum DOT De>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Trouble with getche()
Date:	Wed, 09 Oct 1996 09:02:41 +0100
Organization:	Lehrstuhl fuer Stroemungsmechanik
Lines:	44
Message-ID:	<325B5C21.41C6@LSTM.Ruhr-UNI-Bochum.De>
References:	<325B1E56 DOT 5BDA AT erols DOT com>
NNTP-Posting-Host:	bvb.lstm.ruhr-uni-bochum.de
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

Tony Sideris wrote:
> 
> I'm trying to do this simple little C thing, but it won't work right...I
> copied it right out of a C book.
> Here's what I type:
> main()
> {
>  char ch;
>  printf("Type a character: ");
Just add
   fflush(stdout);


>  ch = getche();
>  printf("\nYou typed: %c", ch);
> }
> 
> After I compile it, I run it and the cursor just goes to next line
> (which is blank) and does nothing. Then, for example, I type p it says:
> 
> pType a character:
> You typed: p
Welcome in the UNIXish world of buffered streams. stdout is
usually flushed when it encounters a \n (or when you printout
n characters not equal \n, where n is typically 16384)
The second line is only printed because the exit() function
flushes and closes (?) stdout.

 

Ciao
Tom

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* Thomas Demmer                                             *
* Lehrstuhl fuer Stroemungsmechanik                         *
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