Date:	Sun, 14 Jan 1996 11:28:15 +0200 (IST)
From:	Eli Zaretskii <eliz AT is DOT elta DOT co DOT il>
To:	"Eric J. Korpela" <korpela AT islay DOT ssl DOT berkeley DOT edu>
Cc:	djgpp AT delorie DOT com
Subject:	Re: (none)

On 11 Jan 1996, Eric J. Korpela wrote:

> In article <DKzMM1 DOT KrA AT jade DOT mv DOT net>,  <kagel AT quasar DOT bloomberg DOT com> wrote:
> >
> >	if (!my_pointer)
> >		my_pointer = (my_struct_t *)malloc( sizeof (my_struct_t) ); 
> >
> >Or BETTER CODE but equivalent:
> >
> >	if (my_pointer == (my_struct_t *)NULL)
> 
> Is this really better?  Could option 1 fail?  I thought the C standard
> guaranteed that the top option would work.

Yes, it *is* better.  ANSI C says that the null pointer (for any type) is 
a zero cast to a pointer to that type, but it doesn't guarantee that the 
bit pattern for the null pointer is all-zero (so that !null_ptr is 
true).  So you could write `if (my_pointer == 0)' (because the compiler 
automatically will cast 0 to the pointer type), but `if (!my_pointer)' 
may not work on some odd architectures.

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