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Message-ID:	<3FFF2420.7090305@phekda.gotadsl.co.uk>
Date:	Fri, 09 Jan 2004 21:58:56 +0000
From:	Richard Dawe <rich AT phekda DOT gotadsl DOT co DOT uk>
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To:	djgpp-workers AT delorie DOT com
Subject:	Re: stdbool.h and complex.h
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In-Reply-To:	<3FFE97BE.4CA94BA3@yahoo.com>
Reply-To:	djgpp-workers AT delorie DOT com

Hello.

CBFalconer wrote:
[snip]
> Injecting _Bool is no problem, using it (under C90) is.  So the
> only problem that can arise is not having the underlying C99
> abilities.  Therefore the proposed stdbool.h is fine, with the
> solitary exception of the "|| STRICT_ANSI" term.

I'm having trouble understanding your point(s).

* C89 doesn't define _Bool.
* Does C90 define _Bool? What is C90?
* C99 does define _Bool.

The C99 sections are protected by:

     (Standard C version defines >= C99) && !(strict ANSI)

If we're using -ansi/-std=c89/-std=gnu89, __STRICT_ANSI__ will be 
defined but the C version defines won't. So the C99 section will *not* 
be included.

If we're using -std=c99/-std=gnu99, then __STRICT_ANSI__ and the C 
version defines are defined. So the C99 section will be included.

If no -ansi/-std switches are used, then __STRICT_ANSI__ is not defined 
and the C99 section will be included. Note that this is independent of 
whatever mode the compiler operates in by default.

So I don't see what the problem is.

Thanks, bye, Rich =]

-- 
Richard Dawe [ http://homepages.nildram.co.uk/~phekda/richdawe/ ]

"You can't evaluate a man by logic alone."
   -- McCoy, "I, Mudd", Star Trek

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