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Date: | Sat, 19 Apr 2003 10:23:38 +0200 |
From: | "Eli Zaretskii" <eliz AT elta DOT co DOT il> |
Sender: | halo1 AT zahav DOT net DOT il |
To: | ams AT ludd DOT luth DOT se |
Message-Id: | <2110-Sat19Apr2003102338+0300-eliz@elta.co.il> |
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CC: | djgpp-workers AT delorie DOT com |
In-reply-to: | <200304171703.h3HH307q016727@speedy.ludd.luth.se> |
(ams AT ludd DOT luth DOT se) | |
Subject: | Re: Long double confusion |
References: | <200304171703 DOT h3HH307q016727 AT speedy DOT ludd DOT luth DOT se> |
Reply-To: | djgpp-workers AT delorie DOT com |
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> From: <ams AT ludd DOT luth DOT se> > Date: Thu, 17 Apr 2003 19:03:00 +0200 (CEST) > > My readings on the net doesn't show what a long double with it > exponent set to 0x7fff and a _cleared_ most significant bit in the > mantissa is. The most significant bit for a long double is the > integer bit (which isn't present in floats or doubles). > > As far as I understand a long double with exponent == 0 and with > the most significant bit in the mantissa cleared is a denormal (which > isn't a NaN but a value close to 0). > > But I don't know what to make of it when exponent != 0. > > Are they all NaNs? Only the ones with exponent == 0x7fff? Or none of > them? See section 7.4.4 of the Intel Manual: it calls those numbers "unnormals". Such numbers are generally a result of interpreting arbitrary bit patterns as FP numbers (a.k.a. "bugs"). IIRC, our _doprnt has special support for those.
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