Mail Archives: djgpp-workers/2000/03/20/10:50:35
On Mon, 20 Mar 2000, Hans-Bernhard Broeker wrote:
> Eli's point of view, as I read it: No, it is not negative, because the
> term 'negative' does not have a valid mathematical meaning for NaNs.
Not only because of this, but also because how Intel treats the real
indefinite. It is clear (to me) from that treatment that they use the
sign bit as a flag, to the effect that this NaN was produced by an
operation wher none of the operands was a NaN.
> My point against this reasoning by Eli is that the word 'negative', if
> found in the C99 standard, does not necessarily mean the same as the word
> 'negative' in mathematics.
IIRC, the standard doesn't say what does it mean by ``negative''.
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