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From:	"Rod Pemberton" <do_not_have AT nohavenot DOT cmm>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: gcc ching.c compile failed
Date:	Mon, 4 Jan 2010 20:02:44 -0500
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"Jude DaShiell" <jdashiel AT shellworld DOT net> wrote in message
news:alpine DOT BSF DOT 2 DOT 00 DOT 1001031620510 DOT 77719 AT freire1 DOT furyyjbeyq DOT arg...
> This program compiles correctly with gcc.  gcc ching.c -o ching <cr>.
> The only output this program generates is the useage message.  I have
> ching.txt located in /usr/local/lib/ching.txt.  What has me puzzled is why
> no other output is available.  Is this a program that needs a different
> compiler?  I can build it with Power C if need be but if such a build
> produces more output, what is the difference that makes gcc work in this
> way?
>

Let's reformat main():

> int main(int argc, char *argv[])
> {
>   int i;
>   char hexagram[6];
>
>   if (argc == 1) {
>   cast(hexagram);
>   i = 6;
>   }
>   else for (i = 0; i < 6 && argv[1][i] >= '6' && argv[1][i] <= '9'; i++)
hexagram[i] = argv[1][i];
>   if (argc > 2 || i < 6) {
>   fprintf(stderr, "usage: %s [hexagram]\n", argv[0]);
>   exit(1);
>   }
>   print(hexagram);
>   if (changing(hexagram)) {
>   fputs("\n", stdout);
>   change(hexagram);
>   print(hexagram);
>   }
>   return 0;
> }

int main(int argc, char *argv[])
{
  int i;
  char hexagram[6];

  if (argc == 1)
  {
    cast(hexagram);
    i = 6;
  }
  else
  {
    for (i = 0; i < 6 && argv[1][i] >= '6' && argv[1][i] <= '9'; i++)
    {
      hexagram[i] = argv[1][i];
    }
  }

  if (argc > 2 || i < 6)
  {
    fprintf(stderr, "usage: %s [hexagram]\n", argv[0]);
    exit(1);
  }

  print(hexagram);
  if (changing(hexagram))
  {
    fputs("\n", stdout);
    change(hexagram);
    print(hexagram);
  }
  return 0;
}


It appears to me that the program must be called with no arguments or one
special argument.  The special argument must be a six digit number with
values for each digit from 6 to 9.  e.g, 777777 or 697886.  If a digit isn't
from 6 to 9, then the "i" value will be less than 6, so the usage message is
displayed.  Notice that's not "argc < 6", but "i < 6".  When six valid
digits are entered, the program attempts to open the path - which doesn't
exist on my system.  Without an argument, it expects some characters from
the keyboard, followed by a return, followed by an EOF (ctrl-Z for DOS).
Then it goes on to attempt to open the path.

Did that help?


Rod Pemberton

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