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From: | Esa A E Peuha <esa DOT peuha AT helsinki DOT fi> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: pointers in Strucrure assignment problem |
Date: | 07 Jul 2005 13:25:39 +0300 |
Organization: | University of Helsinki |
Lines: | 29 |
Message-ID: | <86ppstuoqu4.fsf@sirppi.helsinki.fi> |
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To: | djgpp AT delorie DOT com |
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CBFalconer <cbfalconer AT yahoo DOT com> writes: > > *LD[i].LinePtr = 0; > > How does that bind? I am always deeply suspicious of C's > hierarchy, "Hierarchy"? Oh, you mean operator precedence. In this case it's simple: unary from right always has higher precedence than unary from left. > so I would (in self defense) write: > > *(LD[i].LinePtr) = '\0'; Why? Even if the compiler gets the precedence wrong (which is unlikely), it would then have to dereference a struct. I don't think that any compiler has ever been able to do that without an error. > or even > *((LD[i]).LinePtr) = '\0'; /* for total paranoia */ What, you think the compiler might otherwise parse it as LD([i].LinePtr) and not give an error? :-) -- Esa Peuha student of mathematics at the University of Helsinki http://www.helsinki.fi/~peuha/
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