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Date:	Fri, 21 Jan 2005 18:39:28 +0200
From:	"Eli Zaretskii" <eliz AT gnu DOT org>
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To:	djgpp AT delorie DOT com
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In-reply-to:	<d46153c40501210642184b3371@mail.gmail.com> (message from Andrew
	Paulsen on Fri, 21 Jan 2005 08:42:52 -0600)
Subject:	Re: ls.exe in execv
References:	<d46153c40501210642184b3371 AT mail DOT gmail DOT com>
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> Date: Fri, 21 Jan 2005 08:42:52 -0600
> From: Andrew Paulsen <andrew DOT paulsen AT gmail DOT com>
> 
>  Second, why are you passing the path to ls in the argv[] parameter? 
> The following worked for me:
> 
> #include <unistd.h>
> #include <stdio.h>
> #include <stdlib.h>
> int main() {
> 	int retval;
> 
> 	char *myArgv[] = {"C:\\", NULL};
> 	retval = execv("C:\\djgpp\\bin\\ls.exe",  myArgv);

This is wrong: myArgv[0] should be the program's name, i.e. "ls" or
some such.  myArgv[1] is passed to ls as its 1st command-line
argument.

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