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From:	Michael Beck <beck AT ipd DOT info DOT uni-karlsruhe DOT de>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Inline functions question
Date:	Fri, 23 Apr 2004 16:45:41 +0200
Organization:	University of Karlsruhe, Germany
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Anthony wrote:

> Why does this code
[..]
> inline void A::f2(const char *str)
> {
>     std::cout << "\n __func__ = " << __func__
>             << "\n __PRETTY_FUNCTION__ = " << __PRETTY_FUNCTION__
>             << "\n Caller = " << str;
> }
> 
> void A::f1()
> {
>     std::cout << "\n Now f1() will call f2().";
>     f2(__func__);
> }
[..]
> produces this:
> 
> Now f1() will call f2().
> __func__ = f2        <---- I expected f1
> __PRETTY_FUNCTION__ = void A::f2(const char*)        <---- I expected
> A::f2(...)
> Caller = f1
> 
> The f2() is supposed to be implanted in f1(), no?

Yes, but inlining is done in the optimization phase, while __func__
is typically resolved be the frontend. So, BEFORE f2 is "implanted",
__func__ is already resolved into the constant "f2".

best regards,
-- 
Michael Beck            beck AT ipd DOT info DOT uni-karlsruhe DOT de

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