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| From: | Martin Ambuhl <mambuhl AT earthlink DOT net> |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Re: function question |
| Date: | Sun, 04 Apr 2004 17:27:37 -0400 |
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Bill Cunningham wrote:
> I don't know if it would be better to post this here or comp.lang.c but
> I'll post it here since it's djgpp specific.
If it were djgpp-specific, it is obvious that it goes to
comp.os.msdos.djgpp, not to comp.lang.c, where compiler-specific
questions are off-topic.
However, your question has nothing to do with djgpp, but with basic,
elementary C.
>I'm working on some open source
> programming and seem to have run up against a wall. Can anyone give me any
> pointers(no pun intended) on this.
>
> int ma (int np[])
> {puts("This is number of prices? -> ");
> fflush(stdout);
> puts(int *(np));}
>
> What this function is supossed to do is accept input of a number of prices
> an investor wants to include in a simple moving average. Hince the ma. The
> int * cast is the last thing to my knowledge to try. I know workable C. I'm
> not really experienced with the fancy ins and outs. As the funcion
> continues, it should tally a number of prices and calculate a ma. Then I'll
> include it into a static library where it can be linked with a file
> containing main().
'int *' is not a cast; it's a syntax error. With a cast, the line
puts((int *)np);
makes no sense, and the cast is superfluous as well.
Your argument list suggests that np is an array, with the "code"
suggesting np[0] holds the value you want. This is probably not true.
int ma(int *np)
{
printf("This is number of prices? -> %d\n", *np);
return *np; /* ? */
}
C is really easy if you bother to learn it before coding.
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