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| From: | huli_ebtyt AT list DOT ru (Andrey) |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Re: array size inside of a function |
| Date: | 3 Mar 2004 21:16:35 -0800 |
| Organization: | http://groups.google.com |
| Lines: | 12 |
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| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
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> sizeof(char **) == address size = 4 on 32bit machines. > so in main(), array name is not a pointer? > They simpliest way to get around this is the following: > > function(char *array[], size_t num_elements); > and there no way free from passing size?
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