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From:	Michael Beck <beck AT ipd DOT info DOT uni-karlsruhe DOT de>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: array size inside of a function
Date:	Wed, 03 Mar 2004 10:25:12 +0100
Organization:	University of Karlsruhe, Germany
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Andrey wrote:

> char *array[size];
> 
> function(char *array[])
> {
> 
>  // array[0] returns string #0, but sizeof(array) returns 4
>  // Why returns 4?
>  // Is there any way to get size here?
> }
[..]

This is the way C is specified. function(char *array[]) is simply a "more 
understandable" version of function(char **array), and 

sizeof(char **) == address size = 4 on 32bit machines.

They simpliest way to get around this is the following:

function(char *array[], size_t num_elements);

main() { function(a, sizeof(a)/sizeof(a[0])); }

BTW: Most languages that support this construction (Modula-2 for instance) 
implicit add this parameter :-)

best regards,
-- 
Michael Beck            beck AT ipd DOT info DOT uni-karlsruhe DOT de

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