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Date: | Thu, 30 Oct 2003 08:25:52 -0500 |
Message-Id: | <200310301325.h9UDPqVF020025@envy.delorie.com> |
From: | DJ Delorie <dj AT delorie DOT com> |
To: | djgpp AT delorie DOT com |
In-reply-to: | <oprxuxfe0j0bb83x@news.mad.ttd.net> (message from |
=?iso-8859-15?Q?Rafael_Garc=EDa?= on Thu, 30 Oct 2003 14:07:52 +0100) | |
Subject: | Re: double with only 13 digit precision? |
References: | <oprxuxfe0j0bb83x AT news DOT mad DOT ttd DOT net> |
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In this case, the problem is that the two numbers you are subtracting only have a certain precision *after the decimal*. The result has the same number of digits after the decimal as the numbers you start with. Garbage in, garbage out - try printing them like this: printf("%25.18f\n%25.18f\n%25.18f\n",a,b,c); You'll see: 4777.909999999999854481 4782.979999999999563443 -5.069999999999708962 Note that the 9's all end in the same column.
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